0=9x^2-160x+50

Solution for 0=9x^2-160x+50 equation:

0=9x^2-160x+50

We move all terms to the left:

0-(9x^2-160x+50)=0

We add all the numbers together, and all the variables

-(9x^2-160x+50)=0

We get rid of parentheses

-9x^2+160x-50=0

a = -9; b = 160; c = -50;
Δ = b2-4ac
Δ = 1602-4·(-9)·(-50)
Δ = 23800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23800}=\sqrt{100*238}=\sqrt{100}*\sqrt{238}=10\sqrt{238}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-10\sqrt{238}}{2*-9}=\frac{-160-10\sqrt{238}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+10\sqrt{238}}{2*-9}=\frac{-160+10\sqrt{238}}{-18}
$